how much horsepower would a Challenger SRT® Hellcat Redeye Widebody need to tow the SS Delphine up the industry standard: Davis Dam Grade Climb?

Pro Tips:
Davis Dam assumed grade = 7% Air density is sea level conditions (.002377 slugs/f^t3) w(weight) of the SS Delphine + trailer + Redeye = 3,922,000 + 150,000 + 4451 Lbs Crr = coefficient of rolling resistance = .015 Assume Combined CDA is 1555 ft^2 SAE J2807 (Davis Dam Grande Climb) - min speed is 40mpg (59 ft/s) F(drag) = 1/2p x V^2 x C(d)A F(rolling resistance) = W x cos x Crr F(weight) = W x sin F(sum) = F(drag) + F(rr) + F(weight) P = F(sum)XV convert to horsepower = P(1hp/550ft lbf/sec)

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cybermath cybermath · Answer 1 · 2019-12-03T00:15:46+01:00

Answer: I am getting a result around the 54,800 area, so I am selecting the 55,000 HP answer.

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batolisis batolisis · Answer 2 · 2020-02-11T10:01:44+01:00

Answer:

37769 hp

Step-by-step explanation:

from the pro tips given w ( weight of the SS Delphine + trailer + Redeye) = 3922000 + 150000 + 4451 Lbs Crr = 4076451 ibf

coefficient of rolling resistance = 0.015

Combined CDA = 1555 ft ^2

to get Ф = tan ⁻¹ ( 0.07 ) = 4.0041 degrees

To get F (w) you will multiply it with sin Ф

= F ( w ) = 4076451 ibf * sin( 4.0041 ) = 284655.02 Ibf

to calculate F ( rr ) you will multiply it with cos Ф

F( rr) = 4076451 ibf * 0.015 * cos ( 4.0041 ) = 60997.50 ibf

the total sum of F ( force ) will be

F ( rr ) + F ( w)

= 60997.50 + 284655.02 = 352085.82 Ibf

therefore P ( power ) will be

p = 352085.82 ibf * 59 ft/s = 20773063.27 ft*ibf/s

to calculate how much horsepower the challenger will need to tow the SS Delphine will be calculated as below

HP = (20773063.27 ft*ibf/s ) * ( 1 hp / 550 ft*ibf/s ) = 37769.21 = 37769 hp