Answer:
71 grams of chlorine gas.
Explanation:
2Na + Cl2 = 2NaCl.
From the molar masses:
2(23+35.45) g of NaCl are made from 2*35.45 g Cl2 gas.
So 117 g are made from (2*35.45 * 117) / 2(23+35.45)
= 71 g.
The mass of chlorine gas, Cl₂ needed to make 117 g of sodium chloride, NaCl is 71 g
We'll begin by calculating the mass of Cl₂ that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:
2Na + Cl₂ → 2NaCl
Molar mass of Cl₂ = 2× 35.5 = 71 g/mol
Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g
From the balanced equation above,
71 g of Cl₂ reacted to produce 117 g of NaCl.
Thus, we can conclude that 71 g of chlorine gas, Cl₂ is needed to make 117 g of sodium chloride, NaCl.
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