Respuesta :

Answer:

see explanation

Step-by-step explanation:

Given

(bx + a)(ax + b) = (ax² + b)b ← distribute parenthesis on both sides

abx² + a²x + b²x + ab = abx² + b² ( subtract abx² from both sides )

a²x + b²x + ab = b² ( subtract ab from both sides )

a²x + b²x = b² - ab ← factor out x from each term on the left side

x(a² + b²) = b² - ab ← divide both sides by (a² + b²)

x = [tex]\frac{b^2-ab}{a^2+b^2}[/tex]

altavistard

Answer:

x = -b/a

Step-by-step explanation:

(bx + a)(ax + b) = (ax^2 + b)(b) needs to be muliplied out as a first step to solving for x:

abx^2 + b^2 + a^2x + ab = abx^2 + b^2

Notice that abx^2 shows up on both sides of this equation, so we can cancel it out:

b^2 + a^2x + ab = b^2

Also, b^2 shows up on both sides, so we can also cancel the b^2 terms:

a^2x + ab = 0

Dividing both sides by a, we get ax + b = 0

and so ax = -b,

which means that x = -b/a

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