Respuesta :
One number is 7 less than a second number. Twice the second number is 1 less than 5 times the first. Then the two numbers are 5 and 7
Solution:
Given that one number is 7 less than a second number.
Twice the second number is 1 less than 5 times the first.
Need to determine two numbers.
Let assume first number be represented by variable x and second number be represented by variable y.
As first number is 7 less than a second number, adding 7 to first number will give us second number
=> x + 7 = y ------ (1)
[tex]\begin{array}{l}{\text { Twice of second number }=2 \times \text { second number }=2 \times y=2 y} \\\\ {\text { 5 times the first number }=5 \times \text { first number }=5 \times x=5 x}\end{array}[/tex]
As given that Twice the second number is 1 less than 5 times the first , if we 1 to twice of second number we will get 5 times first number ,
=> 2y + 1 = 5x ------ (2)
On substituting value of y as x + 7 from equation 1 into equation 2 , we get
2(x + 7) + 1 = 5x
=> 2x + 14 + 1 = 5x
=> 2x – 5x = -15
=> -3x = -15
x = 5
Substituting x = 5 in equation (1) to get value of y
=> y = 5 + 7 = 12
Hence first number is 5 and second number is 12
