Respuesta :
Answer:
A. 22 [tex]ms^{-1}[/tex]
B. NO
Explanation:
A.
During a collision , the net external force on the system is zero .
hence , the total momentum of the system can be CONSERVED .
let the mass of frosty and snowflake be m ;
- initial velocity of frosty be [tex]v_{F_{i} }[/tex] = 25 [tex]ms^{-1}[/tex]
- final velocity of frosty be [tex]v_{F_{f} }[/tex] = 13 [tex]ms^{-1}[/tex]
- initial velocity of snowflake be [tex]v_{S_{i} }[/tex] = 10 [tex]ms^{-1}[/tex]
- final velocity of snowflake be [tex]v_{S_{f} }[/tex] = x [tex]ms^{-1}[/tex]
therefore from principle of conservation of momentum ,
[tex]m*v_{F_{i} } + m*v_{S_{i} } = m*v_{F_{f} } + m*v_{S_{f} }[/tex]
so ,
[tex]m*25 + m*10 =m*13 +m*x[/tex]
[tex]x = 25+10-13 = 22 ms^{-1}[/tex]
answer for A. 22 [tex]ms^{-1}[/tex]
B.
The collision is NOT ELASTIC.
this is because if it had been elastic , the coefficient of restitution should have been 1 but it isnot i.e
[tex]e =\frac{ v_{F_{f} } - v_{S_{f} } }{ v_{S_{i} } - v_{F_{i} } } \\=\frac{13-22}{10-25} \\=\frac{9}{15} = \frac{3}{5} = 0.6[/tex] ≠ 1
thus it's an inelastic collision.
