Answer:
Frequency will be 743.09 Hz
Explanation:
We have given maximum speed [tex]v_m=2.66\times 10^{-3}m/sec[/tex]
Amplitude [tex]A=5.7\times 10^{-7}m[/tex]
We have to find the frequency of the vibration
We know that angular frequency is given by
[tex]\omega =\frac{v_m}{A}=\frac{2.66\times 10^{-3}}{5.7\times 10^{-7}}=4666.666rad/sec[/tex]
[tex]2\pi f=4666.66[/tex]
[tex]f=743.09Hz[/tex]
