Answer:
The calcium chloride is an electrolyte salt, so the frezzing point of solution must be higher than ethylene glycol.
Explanation:
This is the colligative property for this question: Frezzing point depression
ΔTf = Kf · molal · i
ΔTf = T° fussion solvent pure - T° fussion solution
As both solutions are the same in molality and the solvent is water, the formula stands the same but the Calcium Chloride is a salt which is dissociated in water like this:
CaCl₂ → Ca²⁺ + 2Cl⁻
We have 3 moles of ions, so this value modiffy the formula with the Van't Hoff Factor (number of ion particles per individual molecule of solute).
Ethyleneglycol is a non-electrolytic organic compound (It is often used 1 as the i).
Let's see the formula in both:
0° - T° fussion solution = Kf · molal · 3 → CaCl2
0° - T° fussion solution = Kf · molal · 1 → C2H6O2
