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Calculate the difference in blood pressur toes of a human by treating the blood as a static fluid (this is a very crude approximation because there is a pump which is making the blcod flow). Assume that the person is 187 cm tall and that the density of bloc d is 1060 kg/m3 use g=10 m/s2). For comparison, normal blood pressure is about 880 mm Hg = 117 kPa, this comprises 760 mm Hg of atmospheric pressure and 120 mm Hg of relative pressure
The difference in blood pressure is ______ kPa

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Answer:

19.822 kPa

Explanation:

[tex]\rho[/tex] = Density of blood = 1060 kg/m³

g = Acceleration due to gravity = 10 m/s²

h = Height of person = 187 cm

The pressure difference would be given by the relation (as there are no other forces to be considered)

[tex]\Delta P=\rho gh\\\Rightarrow \Delta P=1060\times 10\times 1.87\\\Rightarrow \Delta P=19822\ Pa[/tex]

The difference in blood pressure is 19.822 kPa

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