Answer:
6.4 m/s
Explanation:
From the equation of continuity
A1V1=A2V2 where A1 and V1 are area and velocity of inlet respectively while A2 and V2 are the area and velocity of outlet respectively
[tex]A1=\pi (r1)^{2}[/tex]
[tex]A2=\pi (r2)^{2}[/tex]
where r1 and r2 are radius of inlet and outlet respectively
v1 is given as 1.6 m/s
Therefore
[tex]\pi (0.01)^{2}\times 1.6 = \pi (0.005)^{2}v2[/tex]
[tex]V2=\frac {\pi (0.01)^{2}\times 1.6}{\pi (0.005)^{2}}=6.4 m/s[/tex]
