The equation 6x + 4y = 10 written in slope-intercept form is y = -3/2x + 5/2.
How to solve the equation 6x + 4y = 10 by slope-intercept form?
The equation Y = mx + b exists in the slope-intercept form of the equation of a straight line. In the equation y = mx + b, m exists the slope of the line and b exists the intercept. X and y describe the distance of the line from the x-axis and y-axis, respectively. The value of b exists equivalent to y when x = 0, and m indicates how steep the line exists.
Let the equation be, 6x + 4y = 10
Simplifying the above equation we get
4y = 10 - 6x
4y = -6x + 10
y=-6/4x + 10/4
simplify
y = -3/2x + 5/2.
Therefore, the correct answer is option A. y= -3/2x + 5/2.
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