The range is: B. {12, 4, -6}
Step-by-step explanation:
Given
12x + 6y = 24
Here x is the input and y is the output
So,
Replacing y with f(x)
[tex]12x +6f(x) = 24\\6f(x) = 24 - 12x\\\frac{6f(x)}{6} = \frac{24-12x}{6}\\f(x) = \frac{24-12x}{6}[/tex]
Domain = {-4, 0, 5},
We will put the elements of domain, one by one, to find range
[tex]f(-4) = \frac{24-12(-4)}{6}\\=\frac{24+48}{6}\\= \frac{72}{6}\\=12\\\\f(0) = \frac{24-12(0)}{6}\\=\frac{24}{6}\\= 4\\\\f(5) = \frac{24-12(5)}{6}\\=\frac{24-60}{6}\\=\frac{-36}{6}\\=-6[/tex]
Hence,
The range is: B. {12, 4, -6}
Keywords: Range, Domain, functions
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{12, 4, -6}
Step-by-step explanation:
The relation is given by the equation as 12x + 6y = 24 ........... (1)
Now, the domain of this function is {-4, 0, 5}
We have to find the range of this function corresponding to the given domain.
Now, for x = - 4,
12(-4) + 6y = 24 {From equation (1)}
⇒ 6y = 72
⇒ y = 12
Now, for x = 0,
12(0) + 6y = 24 {From equation (1)}
⇒ 6y = 24
⇒ y = 4
Now, for x = 5,
12(5) + 6y = 24 {From equation (1)}
⇒ 6y = -36
⇒ y = -6
Hence, the range for the relation is {12, 4, -6} (Answer)
