Answer:[tex]18.85 rad/s^2[/tex]
Explanation:
Given
mass of turntable [tex]m=0.32 kg[/tex]
radius [tex]r=0.18 m[/tex]
[tex]N=24 rev/s[/tex]
[tex]\omega =2\pi N=2\pi 24[/tex]
[tex]\omega =48\pi rad/s[/tex]
time interval [tex]t=8 s[/tex]
using [tex]\omega =\omeag _0+\alpha t[/tex]
where [tex]\omega =final\ angular\ velocity[/tex]
[tex]\omega _0=initial\ angular\ velocity[/tex]
[tex]\alpha =angular\ acceleration[/tex]
[tex]t=time[/tex]
[tex]48\pi =0+\alpha \times 8[/tex]
[tex]\alpha =6\pi rad/s^2[/tex]
[tex]\alpha =18.85 rad/s^2[/tex]
