The magnitude of the air drag is 784 N
Explanation:
When the airman is falling down, there are two forces acting on him:
- The force of gravity, downward, of magnitude
[tex]F=mg[/tex]
where
m = 80 kg is the mass of the airman
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
- The air drag, upward, of magnitude [tex]F_D[/tex], whose value is proportional to the speed of the airman
At the beginning of the fall, the speed is zero, so the air drag is also zero and therefore the airman starts accelerating due to the presence of the force of gravity, which is unbalanced. However, as the airman falls down, he gains speed, so the magnitude of the air drag increases up to a point where it becomes equal to the magnitude of the force of gravity. When this occurs, the airman no longer accelerates and continues its motion at constant velocity, which is called terminal velocity.
Therefore, at terminal velocity, the air drag is equal to the force of gravity on the airman (the weight), so we can write:
[tex]F_D = mg = (80)(9.8)=784 N[/tex]
Learn more about forces:
brainly.com/question/8459017
brainly.com/question/11292757
brainly.com/question/12978926
#LearnwithBrainly
