Answer:
n = 1.89 x 10¹⁹ photons/s
Explanation:
given,
Power of bulb = 100 W
Visible light = 5 W
wavelength of the visible light = 600 nm
number of photons emitted per second
using formula of wavelength
[tex]\lambda = \dfrac{c}{\nu}[/tex]
[tex]\nu= \dfrac{c}{\lambda}[/tex]
[tex]\nu= \dfrac{3 \times 10^8}{600 \times 10^{-9}}[/tex]
[tex]\nu=5 \times 10^{14}\ Hz[/tex]
energy of photon
U = h υ
U = 6.63 x 10⁻³⁴ x 4 x 10¹⁴
U = 2.65 x 10⁻¹⁹ J
number of photon
[tex]n = \dfrac{P}{U}[/tex]
[tex]n = \dfrac{5}{2.65 \times 10^{-19}}[/tex]
n = 1.89 x 10¹⁹ photons/s
The number of 1.89 x 10¹⁹ photons/s.
From the question, below are the parameters given.
The Visible light = 5 W
The wavelength of the visible light is 600 nm
The number of photons emitted per second
v=c/lander
v=3×10^8/100×10^9
v=<5×10^14
energy of photon
U = h υ
U = 6.63 x 10⁻³⁴ x 4 x 10¹⁴
U = 2.65 x 10⁻¹⁹ J
the number of photon is
8/2.65x 10⁻¹⁹ J
The number of 1.89 x 10¹⁹ photons/s.
Visible light is a part of electromagnetic spectrum that is visible to human eye.
Therefore, The number of 1.89 x 10¹⁹ photons/s.
Learn more about visible light below.
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