Answer:54.70 N
Explanation:
Given
Gauge Pressure of [tex]62.5 cm of H_2O[/tex]
i.e. [tex]h=62.5 cm =0.625 m[/tex]
Effective area [tex]A=51 cm^2[/tex]
initial Pressure[tex]= 1 atm=101.325 kPa[/tex]
Gauge Pressure [tex]P=\rho gh[/tex]
[tex]\rho =density\ of\ water =1000 kg/m^3[/tex]
[tex]P_{gauge}=1000\times 9.8\times 0.625=5.937 kPa[/tex]
Force creates a pressure of [tex]P_1[/tex] which will be equal to Gauge Pressure
[tex]P_1=\frac{F}{A}[/tex]
[tex]P_1=P_{gauge}[/tex]
[tex]\frac{F}{A}=5.937 kPa[/tex]
[tex]F=5.937\times 51\times 10^{-4}\times 10^3[/tex]
[tex]F=30.27 N[/tex]
