Respuesta :
Answer:204.9 N
Explanation:
Given
Radius [tex]r=3.4 in.[/tex]
Density of iron weight [tex]\rho =0.28 pound/in.^3[/tex]
Volume of sphere[tex]=\frac{4\pi r^3}{3}[/tex]
[tex]V=\frac{4\pi (3.4)^3}{3}[/tex]
[tex]V=164.65\ in.^3[/tex]
mass of sphere [tex]m=\rho \cdot V[/tex]
[tex]m=0.28\times 164.65=46.10 Pounds\approx 20.91 kg[/tex]
[tex]weight=mg=20.91\times 9.81=204.91\ N\ or\ 46.063353\ Pound-Force [/tex]
The weigh of the sphere depend on its mass. The weigh of the sphere is 204.722 N.
What is the mass?
Mass is defined as the amount of matter contained in a physical body.
Given that the radius r of the sphere is 3.4 inches and the density [tex]\rho[/tex] of the iron is 0.28 pounds per cubic inch.
The volume of the sphere is calculated as below.
[tex]V = \dfrac {4}{3}\times \pi \times r^3[/tex]
[tex]V = \dfrac {4}{3} \times 3.14\times (3.4)^3[/tex]
[tex]V = 164.55 \;\rm cube\;Inches[/tex]
Now the mass of the sphere is calculated as given below.
[tex]m = \rho \times V[/tex]
[tex]m = 0.28 \times 164.55[/tex]
[tex]m = 46.074 \;\rm Pounds[/tex]
We know that 1 pound is equal to 0.453592 kg. So,
[tex]m = 46.074 \times 0.453592 \;\rm kg[/tex]
[tex]m = 20.89 \;\rm kg[/tex]
The weight of the sphere is given below.
[tex]W = mg[/tex]
Where g is the gravitational acceleration.
[tex]W = 20.89 \times 9.8[/tex]
[tex]W = 204.722 \;\rm N[/tex]
Hence we can conclude that the weigh of the sphere is 204.722 N.
To know more about the mass, follow the link given below.
https://brainly.com/question/19694949.
