Answer:
Explanation:
Given
mass of cart m=20 kg
Force applied F=12 N at angle of [tex]\theta =20^{\circ}[/tex] with horizontal
Force can be resolved in two components i.e. [tex]F\cos \theta [/tex]and [tex]F\sin \theta [/tex]
[tex]F\sin \theta [/tex]is will act Perpendicular to the motion of cart and [tex]F\cos \theta [/tex]will help to move the cart .
Since cart is moving with constant velocity therefore net force is zero on the cart as friction is opposing the [tex]F\cos \theta [/tex]
Work done by [tex]F\cos \theta [/tex]is
[tex]W_1=F\cos \theta \cdot L[/tex]
[tex]W_1=12\cos (20)\cdot 18=202.978 J[/tex]
Work done by Friction will be same but in Opposite Direction
[tex]W_f=-202.978 J[/tex]
Work done by [tex]F\sin \theta [/tex] is
[tex]W_2=0[/tex] because direction of force and motion is Perpendicular to each other.
