Answer:
Frequency, f = 3.35 Hz
Explanation:
It is given that,
Mass of the object, m = 8 kg
Stretching in the spring, x = 2.2 cm
When the spring is hanged up in the Earth's gravitational field, its weight is balanced by the force in the spring. So,
[tex]mg=kx[/tex]
k is the spring constant
[tex]k=\dfrac{mg}{x}[/tex]
[tex]k=\dfrac{8\times 9.8}{2.2\times 10^{-2}}[/tex]
k = 3563.63 N/m
Let f is the frequency of oscillation. Its expression is given by :
[tex]f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}[/tex]
[tex]f=\dfrac{1}{2\pi}\sqrt{\dfrac{3563.63}{8}}[/tex]
f = 3.35 Hz
So, the frequency of oscillation by the spring is 3.35 Hz. Hence, this is the required solution.
