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A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the U-shaped tube until the vertical height of the water column is hW = 19.0 cm .

Respuesta :

The gauge pressure at the water/mercury interface is simply the "head" due to the water:

p = ρgh = 1000kg/m³ * 9.8m/s² * 0.19m = 1862 Pa

If we take the specific gravity of mercury to be 13.6, then the difference in height between the water and mercury columns is

h' = h(1 - 1/s.g.) = 19cm * (1 - 1/13.6) = 17.6 cm

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