For this case we must solve the following system of equations:
[tex]3x-3y = -3\\2x-y = -5[/tex]
To solve we follow the steps below:
We multiply the second equation by -3:
[tex]-6x + 3y = 15[/tex]
Thus, we have the equivalent system:
[tex]3x-3y = -3\\-6x + 3y = 15[/tex]
We add the equations:
[tex]3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4[/tex]
We look for the value of the variable "y":
[tex]2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3[/tex]
Thus, the solution of the system is given by:
[tex](x, y): (- 4, -3)[/tex]
Answer:
[tex](x, y): (- 4, -3)[/tex]
