A game rolls a die 10 times and counts how many times the number 5 or 6 shows up.

(a) If there are a total of seven or more times, the win is 2 dollars.
(b) a total of four or more times but less than seven, the win is 1 dollars.
(c) a total of three or less, the win is 0 dollars.

Write a function called payOut that has an input row array of 10 integers representing the ten rolls of dice, and calculates the pay out.

Let's do this in python. We can start by filtering the result by 5 and 6. Then we will count the number of items in the filtered array. Finally, a conditional statement to output the result.

def payOut(ten_rolls):

five_or_six = [roll for roll in ten_rolls if roll in [5,6]]

count_5_or_6 = len(five_of_six)

if count_5_or_6 >= 7:

return 2

elif count_5_or_6 >=4:

return 1

else return 0

tallinn tallinn · Answer 2 · 2022-02-24T13:16:07+01:00

We are applying the python formula. Then We can start by filtering the result by 5 and also 6.

python

After that Then we will count the number of items in the filtered array. After that the result a conditional statement to output the result. def payOut(ten_rolls): five_or_six = [roll for roll in ten_rolls if roll in [5,6]] count[tex]_5_or_6 =[/tex] len(five_of_six) if count[tex]_5_or_6 >= 7[/tex]: return 2 elif count_5_or_6 >=4: return 1 else return 0

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