Respuesta :
Explanation:
As it is given that both the given containers are at same temperature and pressure, therefore they have the same density.
So, mass of [tex]SF_{6}[/tex] in container- 1 is as follows.
5.35 mol x molar mass of [tex]SF_{6}[/tex]
= 7.61 mol x 146.06 g/mol
= 1111.52 g
Therefore, density of [tex]SF_{6}[/tex] will be calculated as follows.
Density = [tex]\frac{mass}{volume}[/tex]
density = [tex]\frac{1111.52 g}{2.09 L \times 1000 ml/L}[/tex]
= 0.532 g/mL
Now, mass of [tex]SF_{6}[/tex] in container- 2 is calculated as follows.
4.46 L x 1000 mL/L x 0.532 g/mL
= 2372.72 g
Hence, calculate the moles of moles [tex]SF_{6}[/tex] present in container 2 as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{2372.72 g}{146.06 g/mol}[/tex]
= 16.24 mol
Since, 1 mol [tex]SF_{6}[/tex] contains 6 moles F atoms .
So, 16.24 mol [tex]SF_{6}[/tex] contains following number of atoms.
= [tex]16.24 mol \times 6[/tex]
= 97.46 mol
Thus, we can conclude that moles of F atoms in container 2 are 97.46 mol.
