Write an equation In slope intercept form for the line that is parallel to the given line and that passes through the given point

5x - 2y=10 (3 -5)

Respuesta :

The equation of the parallel line in slope-intercept form is;

y = [tex]\frac{5}{2}[/tex] x - [tex]\frac{25}{2}[/tex]

Step-by-step explanation:

Let us revise some facts about parallel lines

The equations of two parallel lines have:

  • Same slopes
  • Different y-intercept

The slope-intercept form of the equation of a line is y = m x + b, where m is the slope of the line and b is the y-intercept

The given line has equation 5x - 2y = 10

Put it in the form of y = m x + b to find its slope

∵ 5x - 2y = 10

- Subtract 5x from both sides

∴ -2y = 10 - 5x

- Divide to sides by -2

∴ y = -5 + [tex]\frac{5}{2}[/tex] x

∴ y =  [tex]\frac{5}{2}[/tex] x - 5

- The value of m is the coefficient of x

∴ m = [tex]\frac{5}{2}[/tex]

∴ The slope of the given line is [tex]\frac{5}{2}[/tex]

∵ Parallel lines have same slopes

∴ The slope of the parallel line is m = [tex]\frac{5}{2}[/tex]

- Substitute the value of m in the form of the equation

∴ The equation of the parallel line is y = [tex]\frac{5}{2}[/tex] x + b

To find b substitute x and y in the equation by the coordinates of any point lies on the line

∵ The parallel line passes through point (3 , -5)

- Substitute x and y by the coordinates of the point (3 , -5)

∵ x = 3 and y = -5

∴ -5 = [tex]\frac{5}{2}[/tex] (3) + b

∴ -5 = [tex]\frac{15}{2}[/tex] + b

- Subtract [tex]\frac{15}{2}[/tex] from both sides

∴ b = [tex]\frac{-25}{2}[/tex]

∴ The equation of the parallel line is y = [tex]\frac{5}{2}[/tex] x + [tex]\frac{-25}{2}[/tex]

∴ The equation of the parallel line is y = [tex]\frac{5}{2}[/tex] x - [tex]\frac{25}{2}[/tex]

The equation of the parallel line in slope-intercept form is;

y = [tex]\frac{5}{2}[/tex] x - [tex]\frac{25}{2}[/tex]

Learn more:

You can learn more about the equations of parallel lines in brainly.com/question/8628615

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