For this case we have the following system of equations:
[tex]x-5y = 33\\5x-6y = 70[/tex]
We multiply the first equation by -5:
[tex]-5x + 25y = -165[/tex]
Thus, we have the equivalent system:
[tex]-5x + 25y = -165\\5x-6y = 70[/tex]
We add the equations:
[tex]-5x + 5x + 25y-6y = -165 + 70\\19y = -95\\y = - \frac {95} {19}\\y = -5[/tex]
We find the value of the variable "x":
[tex]x-5 (-5) = 33\\x + 25 = 33\\x = 33-25\\x = 8[/tex]
Thus, the solution of the system is:
[tex](x, y) :( 8, -5)[/tex]
Answer:
[tex](x, y) :( 8, -5)[/tex]
