contestada

3 When Klorina swims with the current, she swims 10 km
In 2 h. Against the current, she can swim only 8 km in
the same time. How fast can Klorina swim in still water?
What is the rate of the current?

Respuesta :

Speed in still water [tex]=[/tex] 9km

Speed of the current   [tex]=[/tex] 1 km

Answer:

Step-by-step explanation:

Speed of the current [tex]=[/tex] C

Speed of the still water [tex]=[/tex] S

Speed with the current [tex]=[/tex] [tex]([/tex] speed of the still water ₊ speed of the current [tex])[/tex]

                                      [tex]=[/tex] S ₊ C      

Speed with the current [tex]=[/tex] S ₊ C [tex]=[/tex] 10km

Speed against the current [tex]=[/tex] [tex]([/tex] speed of the still water ₋speed of the current [tex])[/tex]

                                              [tex]=[/tex] S ₋ C

Speed against the current [tex]=[/tex] S ₋ C [tex]=[/tex] 8km

Speed in still water [tex]=[/tex] Speed with the current ₊ Speed against the current[tex])[/tex]÷ 2

                                [tex]= ([/tex] 10 ₊ 8 [tex])[/tex] ÷ 2

                                [tex]=[/tex] [tex]([/tex] 18 [tex])[/tex] ÷ 2

Speed in still water [tex]=[/tex] 9km

Speed of the current [tex]= ([/tex] Speed with the current ₋ Speed against the current[tex])[/tex] ÷ 2

                                     [tex]= ([/tex] 10 ₋ 8 [tex])[/tex] ÷ 2

                                     [tex]=[/tex] [tex]([/tex] 2 [tex])[/tex] ÷ 2

Speed of the current   [tex]=[/tex] 1 km