Respuesta :
Answer: The mole fraction of hydrogen gas at 20°C is 0.975
Explanation:
We are given:
Vapor pressure of water vapor at 20°C = 17.5 torr
Total pressure at 20°C = 700.0 torr
Vapor pressure of hydrogen gas at 20°C = (700.0 - 17.5) torr = 682.5 torr
To calculate the mole fraction of hydrogen gas at 20°C, we use the equation given by Raoult's law, which is:
[tex]p_{H_2}=p_T\times \chi_{H_2}[/tex]
where,
[tex]p_{H_2}[/tex] = partial pressure of hydrogen gas = 682.5 torr
[tex]p_T[/tex] = total pressure = 700.0 torr
[tex]\chi_{H_2}[/tex] = mole fraction of hydrogen gas = ?
Putting values in above equation, we get:
[tex]682.5torr=700.0torr\times \chi_{H_2}\\\\\chi_{H_2}=\frac{682.5}{700.0}=0.975[/tex]
Hence, the mole fraction of hydrogen gas at 20°C is 0.975
Answer: 0.975
Explanation:
First, calculate the partial pressure of hydrogen gas. The partial pressure of hydrogen gas, PH2, is the difference between the total pressure and the partial pressure of water vapor.
PH2=700.0 torr−17.5torr=682.5torr
Now, use the following equation to calculate the mole fraction of hydrogen gas.
PH2 = XH2 × Ptotal
XH2 = PH2 / Ptotal
= 682.5 torr / 700.0 torr = 0.975
