Calculate the acceleration of gravity on the surface of the Sun. The mass of the Sun is MSun = 1.99 ✕ 1030 kg, the radius of the Sun is rSun = 6.96 ✕ 108 m, and G = 6.67 ✕ 10−11 N · m2/kg2. m/s2 (b) By what factor would your weight increase if you could stand on the Sun? (Never mind that you can't.) Fg, Sun Fg, Earth =

Respuesta :

Answer: 28

Explanation:

According to Newton's law of Gravitation the gravitational force on the surface of the Sun  [tex]Fg_{s}[/tex] is:

[tex]Fg_{s}=mg_{sun}=G\frac{Mm}{r^{2}}[/tex] (1)

Where:

[tex]m[/tex] is your mass

[tex]g_{sun}[/tex] is the acceleration due gravity on the surface of the Sun

[tex]G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex] is the gravitational constant

[tex]M=1.99(10)^{30} kg[/tex] is the mass of the Sun

[tex]r=6.96(10)^{8} m[/tex] is the radius of the Sun

Simplifying:

[tex]g_{sun}=G\frac{M}{r^{2}}[/tex] (2)

[tex]g_{sun}=6.674(10)^{-11} \frac{m^{3}}{kgs^{2}} \frac{1.99(10)^{30} kg}{(6.96(10)^{8} m)^{2}}[/tex] (3)

[tex]g_{sun}=274 m/s^{2}[/tex] (4)

Since the acceleration due gravity on Earth is [tex]g_{E}=9.8 m/s^{2}[/tex], the relation is:

[tex]\frac{g_{sun}}{g_{E}}=\frac{274 m/s^{2}}{9.8 m/s^{2}}[/tex]

[tex]\frac{g_{sun}}{g_{E}}=27.9 \approx 28[/tex]

Hence, your weight would increase by a factor of 28.