Respuesta :

Answer:

27[tex]\frac{27}{4x^{6}y^{8}  }[/tex]

Step-by-step explanation:

your going to raise the power on the numerator by 3 and the denominator 4  so you get [tex]\frac{4*27x^{6} y^{12} }{16x^{12}y^{20}  }[/tex] then reduce and simplify

[tex]\rightsquigarrow[/tex] [tex]\bold{\dfrac{4(3x^2 y^4)^3}{(2x^3 y^5)^4} }[/tex]

[tex]\rightsquigarrow[/tex] [tex]\bold{\dfrac{4(3x^5 y^{12})}{2x^{12} y^{20}} }[/tex]

[tex]\rightsquigarrow[/tex] [tex]\bold{\dfrac{ 12x^5 y^{12}}{2x^{12} y^{20}} }[/tex]

[tex]\rightsquigarrow[/tex] [tex]\bold{ \dfrac{\cancel{12x^5 y^{12}}}{\cancel{2x^{12} y^{20}}}}[/tex]

[tex]\rightsquigarrow[/tex] [tex]\bold{\dfrac{6}{x^7 y^8} }[/tex]

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