Question 4 Multiple Choice Worth 1 points)
(04.06 MC)
In the graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded and labeled B, and the area where f(x) and g(x) have shading in
common is labeled AB.
9
.
The graph represents which system of inequalities?

Question 4 Multiple Choice Worth 1 points 0406 MC In the graph the area below fx is shaded and labeled A the area below gx is shaded and labeled B and the area class=

Respuesta :

Answer:

[tex]f(x)<-2x+6[/tex]

[tex]g(x) \leq x+2[/tex]

Step-by-step explanation:

step 1

Fin the equation of the linear inequality f(x)

we know that

The solution of the linear inequality f(x) is the shaded area below the dashed line

The y-intercept of the dashed line is (0,6)

The x-intercept of the dashed line is (3,0)

The slope of the dashed line is negative and its value  is equal to

[tex]m=(0-6)\(3-0)=-2[/tex]

The linear function f(x) in slope intercept form is equal to

[tex]f(x)=-2x+6[/tex]

therefore

The linear inequality f(x) is equal to

[tex]f(x)<-2x+6[/tex] ----> is < because is a dashed line and the shaded area is below the line

step 2

Fin the equation of the linear inequality g(x)

we know that

The solution of the linear inequality g(x) is the shaded area below the solid line

The y-intercept of the solid line is (0,2)

The x-intercept of the solid line is (-2,0)

The slope of the solid line is positive and its value  is equal to

[tex]m=(0-2)\(-2-0)=1[/tex]

The linear function g(x) in slope intercept form is equal to

[tex]g(x)=x+2[/tex]

therefore

The linear inequality g(x) is equal to

[tex]g(x) \leq x+2[/tex] ----> is ≤ because is a solid line and the shaded area is below the line

therefore

The system of inequalities  is equal to

[tex]f(x)<-2x+6[/tex]

[tex]g(x) \leq x+2[/tex]