Answer:
[tex]K=-2J+28[/tex]
Step-by-step explanation:
For the given trend line, we need to find the y-intercept and slope of the line for determining its equation.
Equation of a line is of the form [tex]y=mx+b[/tex]
Where, 'm' is the slope and 'b' is the y-intercept.
Here, the variables are 'J' and 'K'.
The y-intercept is the point where the 'J' value is 0. From the graph, when 'J' is 0, then the 'K' value is 28. Therefore, the y-intercept is 28.
Slope is given as the ratio of change in 'K' and change in 'J'
The overall change in 'K' is 0 - 28 = -28.
The overall change in 'J' is 14 - 0 = 14
Therefore, the slope is given as:
[tex]m=\frac{\Delta K}{\Delta J}=\frac{-28}{14}=-2[/tex]
Therefore, the equation of trend line is given as:
[tex]K=-2J+28[/tex]
