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A piston has an external pressure of 8.00 atm. How much work has been done in joules if the cylinder goes from a volume of 0.130 liters to 0.600 liters? Express your answer with the appropriate units.

Respuesta :

Answer:

-381 J

Explanation:

The expression for the calculation of work done is shown below as:

[tex]w=-P\times \Delta V[/tex]

Where, P is the pressure

[tex]\Delta V[/tex] is the change in volume

From the question,  the cylinder goes from a volume of 0.130 liters to 0.600 liters, So,

[tex]\Delta V[/tex] = 0.600- 0.130 L = 0.470 L

P = 8.00 atm

[tex]w=-8.00\times 0.470\ atmL[/tex]

Also, 1 atmL = 101.3 J

So,  

[tex]w=-8.00\times 0.470\times 101.3\ J=-381\ J[/tex] (work is done by the system)

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