Answer:
θ =607.33°
Explanation:
Given that
Angular acceleration α = 3.45 rad/s²
Initial angular speed ,ω = 1.85 rad/s
The angle rotates by wheel in time t
[tex]\theta=\omega t +\dfrac{1}{2}\alpha t^2[/tex]
Now by putting the values
[tex]\theta=\omega t +\dfrac{1}{2}\alpha t^2[/tex]
[tex]\theta=1.85\times 2 +\dfrac{1}{2}\times 3.45\times 2^2[/tex]
θ = 10.6 rad
[tex]\theta=\dfrac{180}{\pi}\times 10.6\ degree[/tex]
θ =607.33°
Therefore angle turn by wheel in 2 s is θ =607.33°
