Answer:
The distance between A and B is l(AB) = 13 units
Step-by-step explanation:
Given:
let,
A ≡ ( x1, y1 ) ≡ ( 0, 12 )
B ≡ ( x2, y2 ) ≡ ( 5, 0 )
To Find:
Length AB = ?
Solution:
Distance Formula for the distance between the two points ( x1, y1 ) and ( x2, y2 ) we have,
[tex]l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}[/tex]
On substituting the above values we will get,
[tex]l(AB) = \sqrt{((5-0)^{2}+(0-12)^{2} )}\\l(AB)=\sqrt{(5^{2} +(-12)^{2} } \\l(AB)=\sqrt{(25+144)}\\ l(AB)=\sqrt{169} \\l(AB)=13\ unit[/tex]
Therefore the distance between A and B is l(AB) = 13 units
