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(a) Steve exerts a steady force of magnitude 210N (about 47 lb.) on the stalled car in fig. 6.3 as he pushesit a distance of 18 m. The care also has a flat tire, so to make the car track straight Steve must push at an angle of 30 degrees to the direction of motion. How much work does Steve do? (b) refer to book.

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Answer:

3 300 J

Explanation:

Work done, mathematically speaking,  is the distance moved multiplied by the force exerted in the only in direction of motion. In this question therefore we will multiply the distance by the component of the force that moved the car forward

W = Fdcosθ

    = 210 N  * 18 * Cos 30°

    = 3 300 J

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