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A 42 kg object is 2.5 m from a 55kg object. How much is the force of attraction between them?

Respuesta :

rafaleo84

Answer:

Force of attraction is 2,46*10^-8N[tex]F= G*(m1*m2/r^2)\\where \\\\G=6,67*10^-11 (N*m^2/kg^2)\\m1=42kg\\m2=55kg\\r=2,5m\\therefore\\F=6,67*10^-11*(42*55/2.5^2)\\

F=2,46*10^-8 N[/tex]

Explanation:

Using the Law of Universal Gravitation, proposed by Newton.

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