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SuperCatLover2000

Answer: 4) 7c ^2d - 7c + 4d - 10

Explanation:

First write equastion as seen:

5c^2d - 4c + 3d - 3 + 2c^d - 3c+ d - 7

Next add the c^2d’s together:

7c^2d - 4c + 3d - 3 + 3c + d - 7

Add the c’s together:

7c^2d - 7c + 3d - 3 + d - 7

Add the d’s:

7c^2d - 7c + 4d - 3 - 7

Lastly add the normal numbers:

7c^2d - 7c + 4d - 10

Thus, that is your answer!

Hope this helps! :)

B3ANI3
((just a formatting note - n^2 is the same as n squared))

To answer the question you have to group all like terms together
(eg n^2 + n^2 is 2n^2)

5c^2d - 4c + 3d - 3 + 2c^2d - 3c + d - 7
First group the similar terms together
5c^2d + 2c^2d - 4c - 3c + 3d + d - 3 - 7
Then add or subtract the terms from each other depending on the symbol separating them
5c^2d + 2c^d = 7c^2d
-4c - 3c = - 7c
3d + d = 4d
-3 - 7 = -10

Then collect the now simplified terms together to make an expression
7c^2d - 7c + 4d - 10
The correct answer is the second box down.

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