Answer:
T=5797.8 K
Explanation:
Given that
Power P = 3.9 x 10²⁶ W
Radius ,r= 6.96 x 10⁸ m
We know that ,From Plank's law
P = σ A T⁴
σ = 5.67 x 10 ⁻⁸
A= Area ,T= Temperature ( in Kelvin)
[tex]T=\left (\dfrac{P}{\sigma A} \right )^{\dfrac{1}{4}}[/tex]
Now by putting the values
[tex]T=\left (\dfrac{P}{\sigma A}\right )^{\dfrac{1}{4}}[/tex]
[tex]T=\left (\dfrac{3.9\times 10^{26}}{5.67\times 10^{-8}\times 4\times \pi \times (6.96\times 10^8)^2} \right )^{\dfrac{1}{4}}[/tex]
T=5797.8 K
The temperature of surface will be 5797.8 K
