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PLEASE HELP! 100 POINTS!!+ BRAINLIEST!!
Two wires help support a pole. The wire at point A forms an angle of 54° with the ground and the wire at point B forms an angle of 72° with the ground. The distance between the wires on the ground is 23 m. Find the height of the pole to the nearest tenth of a meter.

PLEASE HELP 100 POINTS BRAINLIEST Two wires help support a pole The wire at point A forms an angle of 54 with the ground and the wire at point B forms an angle class=

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mintuchoubay

Height of the pole (DC) is 57.2709m

Step-by-step explanation:

Here, Wire DA and Wire DB supports a pole.

Given that Angle, A=54 , B= 72.

Also, AB = 23m

Now, Taking triangle BCD and Using basic trigonometry

Height of pole H = DC

[tex]TanB = \frac{DC}{BC}[/tex]

[tex]BC= \frac{DC}{TanB}[/tex]

Now, Taking triangle ACD and Using basic trigonometry

[tex]TanA = \frac{DC}{AC}[/tex]

[tex]AC= \frac{DC}{TanA}[/tex]

From figure, we know that

AC = AB + BC

AC - BC = AB = 23

Replacing values of AC and BC

[tex]\frac{DC}{TanA} - \frac{DC}{TanB}=23\\

DC(\frac{1}{TanA}-\frac{1}{TanB})=23[/tex]

Now, TanB= Tan72 =3.0776 and TanA = Tan54=1.3763

[tex]DC (\frac{1}{1.3763} - \frac{1}{3.0776})_= 23[/tex]

[tex]DC ( 0.7265-0.3249)= 23[/tex]

[tex]DC ( 0.4016 )= 23[/tex]

[tex]DC = 57.2709 [/tex]

Thus, Height of thepole is 57.2709m

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