At launch the space shuttle weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 162km/h , and at the end of the first 1.00 min its speed is 1620km/h .
the acceleration is constant during each time interval (but not
necessarily the same in both intervals), what distance does the shuttle
travel during the interval from 8.00 s to 1.00 min?

Answer :

dist = 162*t + A(accelaration)*t^2/2 = 162*52+(((1620-162)/52)*52^2)/2 =162*52+((1620-162)*52)/2=46332kilometres

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