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A horizontal uniform bar of mass 2.9 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.74 m from the other end. A monkey of mass 1.45 kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar.

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Answer:

given,

mass of uniform bar = 2.9 Kg

length of string = 3 m

mass of monkey = 1.45 Kg

monkey is sitting at the center

Weight of the beam will also consider to as the center

total downward force  = 2.9 g  + 1.45 g

now tension will balance the force

T₁ + T₂ = 2.9 g  + 1.45 g

T₁ + T₂ = 4.35 g

taking moment about T₂ string

now,

T₁ x (3-0.74) - 4.35 g x (1.5 - 0.74) = 0

T₁ x  2.26 = 32.3988

T₁ = 14.34 N

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