Answer:
y=-5x+1
Step-by-step explanation:
The equation is: y=mx+b
m = the slope of the line
b = the y-intercept (0,b)
The y-intercept is (0,1) so b = (0,1)
So the equation would be y =mx+1
Now in order to calculate the slope, the equation is:
y₂-y₁ over
x₂-x₁
So we should use the points (-3,13) and (1,-7).
-7-13 over (over means a fraction symbol)
1+3
Simplify:
-20 over 4 =-5/1 = -5
M=-5
So the equation is now:
y=-5x+1
Answer:
Step-by-step explanation:
You need to do some solving simultaneously to get these values. Your quadratic equation is of the form
[tex]ax^2+bx+c=y[/tex]
Use the coordinates you've been given to solve 3 equations. It will be super simple if we start with the coordinate (0, 1). Here's why (obvious after some substitution is done):
[tex]a(0)^2+b(0)+c=1[/tex] which gives us that
c = 1. Now we have a variable to plug in for c to solve for a and b. Again, we have coordinates that we can use to create 2 more equations:
[tex]a(-3)^2+b(-3)+1=13[/tex] and, simplified:
9a - 3b = 12
and the second equation is:
[tex]a(1)^2+b(1)+1=-7[/tex] and, simplified:
a + b = -8
Now combine the 2 bold equations and solve by elimination or substitution to find either a or b. I chose elimination and multiplied the second equation by 3 to get a new equation:
3a + 3b = -24
Using the elimination method:
9a - 3b = 12
3a + 3b = -24
You can see that the b's subtract each other away, leaving us with
12a = -12 so
a = -1
Now plug -1 in for a to solve for b:
-1 + b = -8 so
b = -7 and the quadratic is
[tex]-x^2-7x+1=y[/tex]
