Answer:
[tex]K_p=139.6\ MeV[/tex]
Explanation:
It is given that,
The rest energy of a pion is 139.6 MeV. Here, two protons having equal kinetic energy collides elastically. We need to find the minimum kinetic energy of one of these protons necessary to make a pion-antipion pair.
It can be calculated using conservation of energy and momentum, the total energy of the particles gets converted into rest mass energy of new particles. So,
[tex]2K_p=2\times E_{\pi^+}[/tex]
[tex]K_p=\times E_{\pi^+}[/tex]
[tex]K_p=139.6\ MeV[/tex]
So, the minimum kinetic energy of one of these protons necessary to make a pion-antipion pair is 139.6 MeV. Hence, this is the required solution.
