contestada

Jim Bob Airlines has one 57 seat plane. On its last five flights it had 44 passengers from MSY to DFW, 49 passengers from DFW to OKL, 36 passengers from OKL to TUL, 30 passengers from TUL to FWB, and 49 passengers from FWB to MSY. For the last five flights, what was the load factor? (Make sure your answer is accurate to one decimal place)

Respuesta :

letmeanswer

Solution:

Total number of seats in the plane = 57

From MSY to DFW = 44 passangers

From DFW to OKL = 49 passangers

From OKL to TUL = 36 passangers

From TUL to FWB = 30 passangers

From FWB to MYS = 49 passangers

So the average number of seats filled per flight

                                                                = (44+49+36+30+49) / 5

                                                                 = 208/5

                                                                  = 41.6

For the last 5 flights Load factor = Average number of seats filled per flight / Total number of seats in the plane

= 41.6 / 57

= 0.7298

= 72.9%

So for the last five flights the load factor was 72.9%

Otras preguntas