"In a Young’s double-slit experiment, the separation between slits is d and the screen is a distance D from the slits. D is much greater than d and λ is the wavelength of the light. The number of bright fringes per unit width on the screen is: "
A. Dd/λ
B. Dλ/d
C. D/dλ
D. λ/Dd
E. d/Dλ"

Respuesta :

Answer:

The number of bright fringes per unit width on the screen is, [tex]x=\dfrac{\lambda D}{d}[/tex]      

Explanation:

If d is the separation between slits, D is the distance between the slit and the screen and [tex]\lambda[/tex] is the wavelength of the light. Let x is the  number of bright fringes per unit width on the screen is given by :

[tex]x=\dfrac{n\lambda D}{d}[/tex]

[tex]\lambda[/tex] is the wavelength

n is the order

If n = 1,

[tex]x=\dfrac{\lambda D}{d}[/tex]

So, the the number of bright fringes per unit width on the screen is [tex]\dfrac{\lambda D}{d}[/tex]. Hence, the correct option is (B).