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Answer:

There is an 8.22% probability that a randomly selected person has a birthday in November.

Step-by-step explanation:

The theoretical method to find the probability is the division of the number of desired outcomes by the number of total outcomes.

A randomly selected person has a birthday in November

There are 365 days in a year, so the number of total outcomes is 365.

There are 30 days in november, so the number of desired outcomes is 30.

So the probability is

[tex]P = \frac{30}{365} = 0.0822[/tex]

There is an 8.22% probability that a randomly selected person has a birthday in November.

Answer:

The probability of a randomly selected person has a birthday in November is [tex]8.2\%[/tex]

Explanation

A randomly selected person has a birthday in November

The probability of the event is

[tex]$P(B)=\frac{\text { No }of \text { days in november }}{No\ of \text { days in year }}$[/tex]

[tex]$P(B)=\frac{30}{365}$[/tex]

[tex]P(B)=8.2\%[/tex]

Therefore, the probability of a randomly selected person has a birthday in November is [tex]8.2\%[/tex]

Learn more about probability, refer:

  • https://brainly.com/question/13683667
  • https://brainly.com/question/4538149