Answer:
The expected number of vehicles owned to two decimal places is: 1.85.
Step-by-step explanation:
The table to the question is attached.
[tex]E(X) =[/tex]∑[tex]xp(x)[/tex]
Where:
E(X) = expected number of vehicles owned
∑ = Summation
x = number of vehicle owned
p(x) = probability of the vehicle owned
[tex]E(X) = (0 * 0.1) + (1 * 0.35) + (2 * 0.25) + (3 * 0.2) + (4 * 0.1)\\E(X) = 0 + 0.35 + 0.50 + 0.60 + 0.4\\E(X) = 1.85[/tex]
The expected number of vehicles owned is 1.85.
