Answer:
t = 0.0625 s
Explanation:
given,
frequency of SHM = 5 Hz
Amplitude, A = 1.80 cm
time taken to move from x=0 to x = -1.80 cm
we know,
[tex]frequency = \dfrac{1}{time\ period}[/tex]
[tex]f = \dfrac{1}{T}[/tex]
[tex]T = \dfrac{1}{5}[/tex]
T = 0.25 s
T is the time taken complete one cycle
But for SHM to reach x = -1.80 cm time taken will be equal to T/4
now,
[tex]t = \dfrac{T}{4}[/tex]
[tex]t = \dfrac{0.25}{4}[/tex]
t = 0.0625 s
time taken to go from x=0 to x = -1.80 cm is equal to t = 0.0625 s
