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You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.90 A , even for an instant. What is the largest root-mean-square current you can run through this bulb? _______A

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abidemiokin

Answer: 1.34A

Explanation:

Since the wire will break if it exceeds 1.90A current, this will be the maximum current needed.

The root mean square current

Irms = I0/√2

Where I0 is the maximum current given

Irms = 1.90/√2

Irms = 1.34A

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