Answer:
[tex]C=0.122M[/tex]
Explanation:
Total volume:
[tex]V= 0.5 L + 0.3 L + 0.1 L=0.9 L[/tex]
Total acid (H+) moles:
[tex]n_{acid}=0.5 L * 0.5 mol/L=0.25 mol[/tex]
Total base (OH-) moles:
[tex]n_{base}=0.3 L*0.2 mol/L + 0.1 L*0.4mol/L*2=0.14mol[/tex]
Excess acid:
[tex]n_{ex}=0.25 mol - 0.14mol=0.11 mol[/tex]
Concentration:
[tex]C=\frac{0.11mol}{0.9L}=0.122M[/tex]
