Lydia is at a coffee shop and knows

she can spend no more than $65

before tax. She sees this price list in

the coffee shop.

Item

Dark Roast Coffee

Pumpkin Spice Coffee

Breakfast Tea

Price per pound

$7.50

$10.50

$23.50

Part A

Write a number in each blank to complete an inequality Lydia can use to find how

many pounds of Pumpkin Spice coffee, p, she can buy along with 2 pounds of

Dark Roast coffee.

Respuesta :

Answer:

[tex]10.50p+15\leq 65[/tex]

[tex]p\leq \frac{100}{21}[/tex]

Step-by-step explanation:

Let p represent pounds of Pumpkin Spice coffee.

We have been given that Lydia is at a coffee shop and knows  she can spend no more than $65  before tax. She sees this price list in  the coffee shop.

Item                                               Price per pound

Dark Roast Coffee                                 $7.50

Pumpkin Spice Coffee                         $10.50

Breakfast Tea                                       $23.50

Lydia wants to buy  2 pounds of  Dark Roast coffee, so the cost of 2 pounds of Dark Roast coffee would be [tex]\$7.50\times 2=\$15[/tex].

We are told that cost of each pound of Pumpkin Spice coffee is $10.50, so cost of 'p' pounds of Pumpkin Spice coffee would be [tex]10.50p[/tex].

Since Lydia can spend no more than $65  before tax, so the cost of 2 pounds of  Dark Roast coffee and 'p' pounds of Pumpkin Spice coffee must be less than or equal to 65.

We can represent this information in an inequality as:

[tex]10.50p+15\leq 65[/tex]

Therefore, our required inequality would be [tex]10.50p+15\leq 65[/tex].

[tex]10.50p+15-15\leq 65-15[/tex]

[tex]10.50p\leq 50[/tex]

Divide both sides by 10.50:

[tex]\frac{10.50p}{10.50}\leq \frac{50}{10.50}[/tex]

[tex]p\leq \frac{50*2}{10.50*2}[/tex]

[tex]p\leq \frac{100}{21}[/tex]

[tex]p\leq 4.76190[/tex]

Therefore, Lydia can buy less than or equal to [tex]\frac{100}{21}[/tex] pounds of Pumpkin Spice coffee.